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35x^2=13x
We move all terms to the left:
35x^2-(13x)=0
a = 35; b = -13; c = 0;
Δ = b2-4ac
Δ = -132-4·35·0
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{169}=13$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-13}{2*35}=\frac{0}{70} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+13}{2*35}=\frac{26}{70} =13/35 $
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